పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(CBD\right)}_{16}=12\cdot {16}^2+11\cdot {16}^1+13\cdot {16}^0$$

$$12\cdot {16}^2+11\cdot {16}^1+13\cdot {16}^0=3261$$

$$\frac{3261}{10}=326rema\in der1$$

$$\frac{326}{10}=32rema\in der6$$

$$\frac{32}{10}=3rema\in der2$$

$$\frac{3}{10}=0rema\in der3$$

$$1\to 6\to 2\to 3=3261$$

$$3261\left(base10\right)={\left(3261\right)}_{10}$$