పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(BEC\right)}_{16}=11\cdot {16}^2+14\cdot {16}^1+12\cdot {16}^0$$

$$11\cdot {16}^2+14\cdot {16}^1+12\cdot {16}^0=3052$$

$$\frac{3052}{10}=305rema\in der2$$

$$\frac{305}{10}=30rema\in der5$$

$$\frac{30}{10}=3rema\in der0$$

$$\frac{3}{10}=0rema\in der3$$

$$2\to 5\to 0\to 3=3052$$

$$3052\left(base10\right)={\left(3052\right)}_{10}$$