పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(9D1\right)}_{16}=9\cdot {16}^2+13\cdot {16}^1+1\cdot {16}^0$$

$$9\cdot {16}^2+13\cdot {16}^1+1\cdot {16}^0=2513$$

$$\frac{2513}{10}=251rema\in der3$$

$$\frac{251}{10}=25rema\in der1$$

$$\frac{25}{10}=2rema\in der5$$

$$\frac{2}{10}=0rema\in der2$$

$$3\to 1\to 5\to 2=2513$$

$$2513\left(base10\right)={\left(2513\right)}_{10}$$