పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(4D4\right)}_{16}=4\cdot {16}^2+13\cdot {16}^1+4\cdot {16}^0$$

$$4\cdot {16}^2+13\cdot {16}^1+4\cdot {16}^0=1236$$

$$\frac{1236}{10}=123rema\in der6$$

$$\frac{123}{10}=12rema\in der3$$

$$\frac{12}{10}=1rema\in der2$$

$$\frac{1}{10}=0rema\in der1$$

$$6\to 3\to 2\to 1=1236$$

$$1236\left(base10\right)={\left(1236\right)}_{10}$$