పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(4D1\right)}_{16}=4\cdot {16}^2+13\cdot {16}^1+1\cdot {16}^0$$

$$4\cdot {16}^2+13\cdot {16}^1+1\cdot {16}^0=1233$$

$$\frac{1233}{10}=123rema\in der3$$

$$\frac{123}{10}=12rema\in der3$$

$$\frac{12}{10}=1rema\in der2$$

$$\frac{1}{10}=0rema\in der1$$

$$3\to 3\to 2\to 1=1233$$

$$1233\left(base10\right)={\left(1233\right)}_{10}$$