పరిష్కారం - Tiger Algebra Solver పరిష్కారాన్ని

$${\left(2D8\right)}_{16}=2\cdot {16}^2+13\cdot {16}^1+8\cdot {16}^0$$

$$2\cdot {16}^2+13\cdot {16}^1+8\cdot {16}^0=728$$

$$\frac{728}{10}=72rema\in der8$$

$$\frac{72}{10}=7rema\in der2$$

$$\frac{7}{10}=0rema\in der7$$

$$8\to 2\to 7=728$$

$$728\left(base10\right)={\left(728\right)}_{10}$$