Step by Step Solution
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(2x2 • x) - 15 = 0Step 2 :
Trying to factor as a Difference of Cubes:
2.1 Factoring: 2x3-15
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 2 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
2.2 Find roots (zeroes) of : F(x) = 2x3-15
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 2 and the Trailing Constant is -15.
The factor(s) are:
of the Leading Coefficient : 1,2
of the Trailing Constant : 1 ,3 ,5 ,15
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | -17.00 | ||||||
-1 | 2 | -0.50 | -15.25 | ||||||
-3 | 1 | -3.00 | -69.00 | ||||||
-3 | 2 | -1.50 | -21.75 | ||||||
-5 | 1 | -5.00 | -265.00 | ||||||
-5 | 2 | -2.50 | -46.25 | ||||||
-15 | 1 | -15.00 | -6765.00 | ||||||
-15 | 2 | -7.50 | -858.75 | ||||||
1 | 1 | 1.00 | -13.00 | ||||||
1 | 2 | 0.50 | -14.75 | ||||||
3 | 1 | 3.00 | 39.00 | ||||||
3 | 2 | 1.50 | -8.25 | ||||||
5 | 1 | 5.00 | 235.00 | ||||||
5 | 2 | 2.50 | 16.25 | ||||||
15 | 1 | 15.00 | 6735.00 | ||||||
15 | 2 | 7.50 | 828.75 |
Polynomial Roots Calculator found no rational roots
Equation at the end of step 2 :
2x3 - 15 = 0
Step 3 :
Solving a Single Variable Equation :
3.1 Solve : 2x3-15 = 0
Add 15 to both sides of the equation :
2x3 = 15
Divide both sides of the equation by 2:
x3 = 15/2 = 7.500
When two things are equal, their cube roots are equal. Taking the cube root of the two sides of the equation we get:
x = ∛ 15/2
The equation has one real solution
This solution is x = ∛ 7.500 = 1.95743
One solution was found :
x = ∛ 7.500 = 1.95743How did we do?
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