தீர்வு - tiger-algebra-solver

$${\left(FCD\right)}_{16}=15\cdot {16}^2+12\cdot {16}^1+13\cdot {16}^0$$

$$15\cdot {16}^2+12\cdot {16}^1+13\cdot {16}^0=4045$$

$$\frac{4045}{10}=404rema\in der5$$

$$\frac{404}{10}=40rema\in der4$$

$$\frac{40}{10}=4rema\in der0$$

$$\frac{4}{10}=0rema\in der4$$

$$5\to 4\to 0\to 4=4045$$

$$4045\left(base10\right)={\left(4045\right)}_{10}$$