தீர்வு - tiger-algebra-solver

$${\left(ACD\right)}_{16}=10\cdot {16}^2+12\cdot {16}^1+13\cdot {16}^0$$

$$10\cdot {16}^2+12\cdot {16}^1+13\cdot {16}^0=2765$$

$$\frac{2765}{10}=276rema\in der5$$

$$\frac{276}{10}=27rema\in der6$$

$$\frac{27}{10}=2rema\in der7$$

$$\frac{2}{10}=0rema\in der2$$

$$5\to 6\to 7\to 2=2765$$

$$2765\left(base10\right)={\left(2765\right)}_{10}$$