தீர்வு - tiger-algebra-solver

$${\left(9E2\right)}_{16}=9\cdot {16}^2+14\cdot {16}^1+2\cdot {16}^0$$

$$9\cdot {16}^2+14\cdot {16}^1+2\cdot {16}^0=2530$$

$$\frac{2530}{10}=253rema\in der0$$

$$\frac{253}{10}=25rema\in der3$$

$$\frac{25}{10}=2rema\in der5$$

$$\frac{2}{10}=0rema\in der2$$

$$0\to 3\to 5\to 2=2530$$

$$2530\left(base10\right)={\left(2530\right)}_{10}$$