தீர்வு - tiger-algebra-solver

$${\left(9C2\right)}_{16}=9\cdot {16}^2+12\cdot {16}^1+2\cdot {16}^0$$

$$9\cdot {16}^2+12\cdot {16}^1+2\cdot {16}^0=2498$$

$$\frac{2498}{10}=249rema\in der8$$

$$\frac{249}{10}=24rema\in der9$$

$$\frac{24}{10}=2rema\in der4$$

$$\frac{2}{10}=0rema\in der2$$

$$8\to 9\to 4\to 2=2498$$

$$2498\left(base10\right)={\left(2498\right)}_{10}$$