தீர்வு - tiger-algebra-solver

$${\left(8C0\right)}_{16}=8\cdot {16}^2+12\cdot {16}^1+0\cdot {16}^0$$

$$8\cdot {16}^2+12\cdot {16}^1+0\cdot {16}^0=2240$$

$$\frac{2240}{10}=224rema\in der0$$

$$\frac{224}{10}=22rema\in der4$$

$$\frac{22}{10}=2rema\in der2$$

$$\frac{2}{10}=0rema\in der2$$

$$0\to 4\to 2\to 2=2240$$

$$2240\left(base10\right)={\left(2240\right)}_{10}$$