தீர்வு - tiger-algebra-solver

$${\left(8B0\right)}_{16}=8\cdot {16}^2+11\cdot {16}^1+0\cdot {16}^0$$

$$8\cdot {16}^2+11\cdot {16}^1+0\cdot {16}^0=2224$$

$$\frac{2224}{10}=222rema\in der4$$

$$\frac{222}{10}=22rema\in der2$$

$$\frac{22}{10}=2rema\in der2$$

$$\frac{2}{10}=0rema\in der2$$

$$4\to 2\to 2\to 2=2224$$

$$2224\left(base10\right)={\left(2224\right)}_{10}$$