தீர்வு - tiger-algebra-solver

$${\left(8A3\right)}_{16}=8\cdot {16}^2+10\cdot {16}^1+3\cdot {16}^0$$

$$8\cdot {16}^2+10\cdot {16}^1+3\cdot {16}^0=2211$$

$$\frac{2211}{10}=221rema\in der1$$

$$\frac{221}{10}=22rema\in der1$$

$$\frac{22}{10}=2rema\in der2$$

$$\frac{2}{10}=0rema\in der2$$

$$1\to 1\to 2\to 2=2211$$

$$2211\left(base10\right)={\left(2211\right)}_{10}$$