தீர்வு - tiger-algebra-solver

$${\left(7B9\right)}_{16}=7\cdot {16}^2+11\cdot {16}^1+9\cdot {16}^0$$

$$7\cdot {16}^2+11\cdot {16}^1+9\cdot {16}^0=1977$$

$$\frac{1977}{10}=197rema\in der7$$

$$\frac{197}{10}=19rema\in der7$$

$$\frac{19}{10}=1rema\in der9$$

$$\frac{1}{10}=0rema\in der1$$

$$7\to 7\to 9\to 1=1977$$

$$1977\left(base10\right)={\left(1977\right)}_{10}$$