தீர்வு - tiger-algebra-solver

$${\left(6B0\right)}_{16}=6\cdot {16}^2+11\cdot {16}^1+0\cdot {16}^0$$

$$6\cdot {16}^2+11\cdot {16}^1+0\cdot {16}^0=1712$$

$$\frac{1712}{10}=171rema\in der2$$

$$\frac{171}{10}=17rema\in der1$$

$$\frac{17}{10}=1rema\in der7$$

$$\frac{1}{10}=0rema\in der1$$

$$2\to 1\to 7\to 1=1712$$

$$1712\left(base10\right)={\left(1712\right)}_{10}$$