தீர்வு - tiger-algebra-solver

$${\left(6A3\right)}_{16}=6\cdot {16}^2+10\cdot {16}^1+3\cdot {16}^0$$

$$6\cdot {16}^2+10\cdot {16}^1+3\cdot {16}^0=1699$$

$$\frac{1699}{10}=169rema\in der9$$

$$\frac{169}{10}=16rema\in der9$$

$$\frac{16}{10}=1rema\in der6$$

$$\frac{1}{10}=0rema\in der1$$

$$9\to 9\to 6\to 1=1699$$

$$1699\left(base10\right)={\left(1699\right)}_{10}$$