தீர்வு - tiger-algebra-solver

$${\left(3E5\right)}_{16}=3\cdot {16}^2+14\cdot {16}^1+5\cdot {16}^0$$

$$3\cdot {16}^2+14\cdot {16}^1+5\cdot {16}^0=997$$

$$\frac{997}{10}=99rema\in der7$$

$$\frac{99}{10}=9rema\in der9$$

$$\frac{9}{10}=0rema\in der9$$

$$7\to 9\to 9=997$$

$$997\left(base10\right)={\left(997\right)}_{10}$$