தீர்வு - tiger-algebra-solver

$${\left(3D8\right)}_{16}=3\cdot {16}^2+13\cdot {16}^1+8\cdot {16}^0$$

$$3\cdot {16}^2+13\cdot {16}^1+8\cdot {16}^0=984$$

$$\frac{984}{10}=98rema\in der4$$

$$\frac{98}{10}=9rema\in der8$$

$$\frac{9}{10}=0rema\in der9$$

$$4\to 8\to 9=984$$

$$984\left(base10\right)={\left(984\right)}_{10}$$