தீர்வு - tiger-algebra-solver

$${\left(3A6\right)}_{16}=3\cdot {16}^2+10\cdot {16}^1+6\cdot {16}^0$$

$$3\cdot {16}^2+10\cdot {16}^1+6\cdot {16}^0=934$$

$$\frac{934}{10}=93rema\in der4$$

$$\frac{93}{10}=9rema\in der3$$

$$\frac{9}{10}=0rema\in der9$$

$$4\to 3\to 9=934$$

$$934\left(base10\right)={\left(934\right)}_{10}$$