தீர்வு - tiger-algebra-solver

$${\left(3A4\right)}_{16}=3\cdot {16}^2+10\cdot {16}^1+4\cdot {16}^0$$

$$3\cdot {16}^2+10\cdot {16}^1+4\cdot {16}^0=932$$

$$\frac{932}{10}=93rema\in der2$$

$$\frac{93}{10}=9rema\in der3$$

$$\frac{9}{10}=0rema\in der9$$

$$2\to 3\to 9=932$$

$$932\left(base10\right)={\left(932\right)}_{10}$$