தீர்வு - tiger-algebra-solver

$${\left(3A3\right)}_{16}=3\cdot {16}^2+10\cdot {16}^1+3\cdot {16}^0$$

$$3\cdot {16}^2+10\cdot {16}^1+3\cdot {16}^0=931$$

$$\frac{931}{10}=93rema\in der1$$

$$\frac{93}{10}=9rema\in der3$$

$$\frac{9}{10}=0rema\in der9$$

$$1\to 3\to 9=931$$

$$931\left(base10\right)={\left(931\right)}_{10}$$