தீர்வு - tiger-algebra-solver

$${\left(3A0\right)}_{16}=3\cdot {16}^2+10\cdot {16}^1+0\cdot {16}^0$$

$$3\cdot {16}^2+10\cdot {16}^1+0\cdot {16}^0=928$$

$$\frac{928}{10}=92rema\in der8$$

$$\frac{92}{10}=9rema\in der2$$

$$\frac{9}{10}=0rema\in der9$$

$$8\to 2\to 9=928$$

$$928\left(base10\right)={\left(928\right)}_{10}$$