தீர்வு - tiger-algebra-solver

$${\left(1D9\right)}_{16}=1\cdot {16}^2+13\cdot {16}^1+9\cdot {16}^0$$

$$1\cdot {16}^2+13\cdot {16}^1+9\cdot {16}^0=473$$

$$\frac{473}{10}=47rema\in der3$$

$$\frac{47}{10}=4rema\in der7$$

$$\frac{4}{10}=0rema\in der4$$

$$3\to 7\to 4=473$$

$$473\left(base10\right)={\left(473\right)}_{10}$$