தீர்வு - tiger-algebra-solver

$${\left(1B8\right)}_{16}=1\cdot {16}^2+11\cdot {16}^1+8\cdot {16}^0$$

$$1\cdot {16}^2+11\cdot {16}^1+8\cdot {16}^0=440$$

$$\frac{440}{10}=44rema\in der0$$

$$\frac{44}{10}=4rema\in der4$$

$$\frac{4}{10}=0rema\in der4$$

$$0\to 4\to 4=440$$

$$440\left(base10\right)={\left(440\right)}_{10}$$