தீர்வு - tiger-algebra-solver

$${\left(1B6\right)}_{16}=1\cdot {16}^2+11\cdot {16}^1+6\cdot {16}^0$$

$$1\cdot {16}^2+11\cdot {16}^1+6\cdot {16}^0=438$$

$$\frac{438}{10}=43rema\in der8$$

$$\frac{43}{10}=4rema\in der3$$

$$\frac{4}{10}=0rema\in der4$$

$$8\to 3\to 4=438$$

$$438\left(base10\right)={\left(438\right)}_{10}$$