Ufumbuzi - Tiger algebra Suluhishaji

4, 090

4,090

Maelezo kwa hatua

${(F F A)}_{16} = b a s e 10$

$F F A$ , $16$ , $10$ .

${(F F A)}_{16} = 15 \cdot 16^{2} + 15 \cdot 16^{1} + 10 \cdot 16^{0}$

$15 \cdot 16^{2} + 15 \cdot 16^{1} + 10 \cdot 16^{0} = 4090$

Hatua: $15 \cdot 16^{2}$
+ $15 \cdot 16^{1}$
+ $10 \cdot 16^{0}$ = $4, 090$ .

$\frac{4090}{10} = 409 r e m a \in d e r 0$

$\frac{409}{10} = 40 r e m a \in d e r 9$

$\frac{40}{10} = 4 r e m a \in d e r 0$

$\frac{4}{10} = 0 r e m a \in d e r 4$

$0 \to 9 \to 0 \to 4 = 4090$

$4090 (b a s e 10) = {(4090)}_{10}$

$4, 090_{10} = 4, 090_{10}$ .

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