Ufumbuzi - Tiger algebra Suluhishaji

3, 820

3,820

Maelezo kwa hatua

${(exists; C)}_{16} = b a s e 10$

$exists; C$ , $16$ , $10$ .

${(exists; C)}_{16} = 14 \cdot 16^{2} + 14 \cdot 16^{1} + 12 \cdot 16^{0}$

$14 \cdot 16^{2} + 14 \cdot 16^{1} + 12 \cdot 16^{0} = 3820$

Hatua: $14 \cdot 16^{2}$
+ $14 \cdot 16^{1}$
+ $12 \cdot 16^{0}$ = $3, 820$ .

$\frac{3820}{10} = 382 r e m a \in d e r 0$

$\frac{382}{10} = 38 r e m a \in d e r 2$

$\frac{38}{10} = 3 r e m a \in d e r 8$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$0 \to 2 \to 8 \to 3 = 3820$

$3820 (b a s e 10) = {(3820)}_{10}$

$3, 820_{10} = 3, 820_{10}$ .

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