Ufumbuzi - Tiger algebra Suluhishaji

14

Maelezo kwa hatua

${(E)}_{16} = b a s e 10$

$E$ , $16$ , $10$ .

${(E)}_{16}$

Hatua: $14 \cdot 16^{0}$ = $14$ .

$14 \cdot 16^{0}$

Hatua: $14 \cdot 16^{0}$ = $14$ .

$14$

Hatua: $14 \cdot 16^{0}$ = $14$ .

$14 (b a s e 10)$

$14_{10} = 14_{10}$ .

$\frac{14}{10}$

$14_{10} = 14_{10}$ .

$14 = 10 \cdot 1 + 4$

$14_{10} = 14_{10}$ .

$1 = 10 \cdot 0 + 1$

$14_{10} = 14_{10}$ .

$14$

$14_{10} = 14_{10}$ .

${(14)}_{10}$

$14_{10} = 14_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

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