Ufumbuzi - Tiger algebra Suluhishaji

3, 579

3,579

Maelezo kwa hatua

${(D F B)}_{16} = b a s e 10$

$D F B$ , $16$ , $10$ .

${(D F B)}_{16} = 13 \cdot 16^{2} + 15 \cdot 16^{1} + 11 \cdot 16^{0}$

$13 \cdot 16^{2} + 15 \cdot 16^{1} + 11 \cdot 16^{0} = 3579$

Hatua: $13 \cdot 16^{2}$
+ $15 \cdot 16^{1}$
+ $11 \cdot 16^{0}$ = $3, 579$ .

$\frac{3579}{10} = 357 r e m a \in d e r 9$

$\frac{357}{10} = 35 r e m a \in d e r 7$

$\frac{35}{10} = 3 r e m a \in d e r 5$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$9 \to 7 \to 5 \to 3 = 3579$

$3579 (b a s e 10) = {(3579)}_{10}$

$3, 579_{10} = 3, 579_{10}$ .

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