Ufumbuzi - Tiger algebra Suluhishaji

3, 567

3,567

Maelezo kwa hatua

${(D E F)}_{16} = b a s e 10$

$D E F$ , $16$ , $10$ .

${(D E F)}_{16} = 13 \cdot 16^{2} + 14 \cdot 16^{1} + 15 \cdot 16^{0}$

$13 \cdot 16^{2} + 14 \cdot 16^{1} + 15 \cdot 16^{0} = 3567$

Hatua: $13 \cdot 16^{2}$
+ $14 \cdot 16^{1}$
+ $15 \cdot 16^{0}$ = $3, 567$ .

$\frac{3567}{10} = 356 r e m a \in d e r 7$

$\frac{356}{10} = 35 r e m a \in d e r 6$

$\frac{35}{10} = 3 r e m a \in d e r 5$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$7 \to 6 \to 5 \to 3 = 3567$

$3567 (b a s e 10) = {(3567)}_{10}$

$3, 567_{10} = 3, 567_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.