Ufumbuzi - Tiger algebra Suluhishaji

3, 499

3,499

Maelezo kwa hatua

${(D A B)}_{16} = b a s e 10$

$D A B$ , $16$ , $10$ .

${(D A B)}_{16} = 13 \cdot 16^{2} + 10 \cdot 16^{1} + 11 \cdot 16^{0}$

$13 \cdot 16^{2} + 10 \cdot 16^{1} + 11 \cdot 16^{0} = 3499$

Hatua: $13 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $11 \cdot 16^{0}$ = $3, 499$ .

$\frac{3499}{10} = 349 r e m a \in d e r 9$

$\frac{349}{10} = 34 r e m a \in d e r 9$

$\frac{34}{10} = 3 r e m a \in d e r 4$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$9 \to 9 \to 4 \to 3 = 3499$

$3499 (b a s e 10) = {(3499)}_{10}$

$3, 499_{10} = 3, 499_{10}$ .

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