Ufumbuzi - Tiger algebra Suluhishaji

3, 324

3,324

Maelezo kwa hatua

${(C F C)}_{16} = b a s e 10$

$C F C$ , $16$ , $10$ .

${(C F C)}_{16} = 12 \cdot 16^{2} + 15 \cdot 16^{1} + 12 \cdot 16^{0}$

$12 \cdot 16^{2} + 15 \cdot 16^{1} + 12 \cdot 16^{0} = 3324$

Hatua: $12 \cdot 16^{2}$
+ $15 \cdot 16^{1}$
+ $12 \cdot 16^{0}$ = $3, 324$ .

$\frac{3324}{10} = 332 r e m a \in d e r 4$

$\frac{332}{10} = 33 r e m a \in d e r 2$

$\frac{33}{10} = 3 r e m a \in d e r 3$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$4 \to 2 \to 3 \to 3 = 3324$

$3324 (b a s e 10) = {(3324)}_{10}$

$3, 324_{10} = 3, 324_{10}$ .

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