Ufumbuzi - Tiger algebra Suluhishaji

3, 293

3,293

Maelezo kwa hatua

${(C D D)}_{16} = b a s e 10$

$C D D$ , $16$ , $10$ .

${(C D D)}_{16} = 12 \cdot 16^{2} + 13 \cdot 16^{1} + 13 \cdot 16^{0}$

$12 \cdot 16^{2} + 13 \cdot 16^{1} + 13 \cdot 16^{0} = 3293$

Hatua: $12 \cdot 16^{2}$
+ $13 \cdot 16^{1}$
+ $13 \cdot 16^{0}$ = $3, 293$ .

$\frac{3293}{10} = 329 r e m a \in d e r 3$

$\frac{329}{10} = 32 r e m a \in d e r 9$

$\frac{32}{10} = 3 r e m a \in d e r 2$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$3 \to 9 \to 2 \to 3 = 3293$

$3293 (b a s e 10) = {(3293)}_{10}$

$3, 293_{10} = 3, 293_{10}$ .

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