Ufumbuzi - Tiger algebra Suluhishaji

3, 261

3,261

Maelezo kwa hatua

${(C B D)}_{16} = b a s e 10$

$C B D$ , $16$ , $10$ .

${(C B D)}_{16} = 12 \cdot 16^{2} + 11 \cdot 16^{1} + 13 \cdot 16^{0}$

$12 \cdot 16^{2} + 11 \cdot 16^{1} + 13 \cdot 16^{0} = 3261$

Hatua: $12 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $13 \cdot 16^{0}$ = $3, 261$ .

$\frac{3261}{10} = 326 r e m a \in d e r 1$

$\frac{326}{10} = 32 r e m a \in d e r 6$

$\frac{32}{10} = 3 r e m a \in d e r 2$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$1 \to 6 \to 2 \to 3 = 3261$

$3261 (b a s e 10) = {(3261)}_{10}$

$3, 261_{10} = 3, 261_{10}$ .

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