Ufumbuzi - Tiger algebra Suluhishaji

3, 055

3,055

Maelezo kwa hatua

${(B E F)}_{16} = b a s e 10$

$B E F$ , $16$ , $10$ .

${(B E F)}_{16} = 11 \cdot 16^{2} + 14 \cdot 16^{1} + 15 \cdot 16^{0}$

$11 \cdot 16^{2} + 14 \cdot 16^{1} + 15 \cdot 16^{0} = 3055$

Hatua: $11 \cdot 16^{2}$
+ $14 \cdot 16^{1}$
+ $15 \cdot 16^{0}$ = $3, 055$ .

$\frac{3055}{10} = 305 r e m a \in d e r 5$

$\frac{305}{10} = 30 r e m a \in d e r 5$

$\frac{30}{10} = 3 r e m a \in d e r 0$

$\frac{3}{10} = 0 r e m a \in d e r 3$

$5 \to 5 \to 0 \to 3 = 3055$

$3055 (b a s e 10) = {(3055)}_{10}$

$3, 055_{10} = 3, 055_{10}$ .

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