Ufumbuzi - Tiger algebra Suluhishaji

2, 750

2,750

Maelezo kwa hatua

${(A B E)}_{16} = b a s e 10$

$A B E$ , $16$ , $10$ .

${(A B E)}_{16} = 10 \cdot 16^{2} + 11 \cdot 16^{1} + 14 \cdot 16^{0}$

$10 \cdot 16^{2} + 11 \cdot 16^{1} + 14 \cdot 16^{0} = 2750$

Hatua: $10 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $14 \cdot 16^{0}$ = $2, 750$ .

$\frac{2750}{10} = 275 r e m a \in d e r 0$

$\frac{275}{10} = 27 r e m a \in d e r 5$

$\frac{27}{10} = 2 r e m a \in d e r 7$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$0 \to 5 \to 7 \to 2 = 2750$

$2750 (b a s e 10) = {(2750)}_{10}$

$2, 750_{10} = 2, 750_{10}$ .

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