Ufumbuzi - Tiger algebra Suluhishaji

2, 513

2,513

Maelezo kwa hatua

${(9 D 1)}_{16} = b a s e 10$

$9 D 1$ , $16$ , $10$ .

${(9 D 1)}_{16} = 9 \cdot 16^{2} + 13 \cdot 16^{1} + 1 \cdot 16^{0}$

$9 \cdot 16^{2} + 13 \cdot 16^{1} + 1 \cdot 16^{0} = 2513$

Hatua: $9 \cdot 16^{2}$
+ $13 \cdot 16^{1}$
+ $1 \cdot 16^{0}$ = $2, 513$ .

$\frac{2513}{10} = 251 r e m a \in d e r 3$

$\frac{251}{10} = 25 r e m a \in d e r 1$

$\frac{25}{10} = 2 r e m a \in d e r 5$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$3 \to 1 \to 5 \to 2 = 2513$

$2513 (b a s e 10) = {(2513)}_{10}$

$2, 513_{10} = 2, 513_{10}$ .

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