Ufumbuzi - Tiger algebra Suluhishaji

2, 501

2,501

Maelezo kwa hatua

${(9 C 5)}_{16} = b a s e 10$

$9 C 5$ , $16$ , $10$ .

${(9 C 5)}_{16} = 9 \cdot 16^{2} + 12 \cdot 16^{1} + 5 \cdot 16^{0}$

$9 \cdot 16^{2} + 12 \cdot 16^{1} + 5 \cdot 16^{0} = 2501$

Hatua: $9 \cdot 16^{2}$
+ $12 \cdot 16^{1}$
+ $5 \cdot 16^{0}$ = $2, 501$ .

$\frac{2501}{10} = 250 r e m a \in d e r 1$

$\frac{250}{10} = 25 r e m a \in d e r 0$

$\frac{25}{10} = 2 r e m a \in d e r 5$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$1 \to 0 \to 5 \to 2 = 2501$

$2501 (b a s e 10) = {(2501)}_{10}$

$2, 501_{10} = 2, 501_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.