Ufumbuzi - Tiger algebra Suluhishaji

2, 498

2,498

Maelezo kwa hatua

${(9 C 2)}_{16} = b a s e 10$

$9 C 2$ , $16$ , $10$ .

${(9 C 2)}_{16} = 9 \cdot 16^{2} + 12 \cdot 16^{1} + 2 \cdot 16^{0}$

$9 \cdot 16^{2} + 12 \cdot 16^{1} + 2 \cdot 16^{0} = 2498$

Hatua: $9 \cdot 16^{2}$
+ $12 \cdot 16^{1}$
+ $2 \cdot 16^{0}$ = $2, 498$ .

$\frac{2498}{10} = 249 r e m a \in d e r 8$

$\frac{249}{10} = 24 r e m a \in d e r 9$

$\frac{24}{10} = 2 r e m a \in d e r 4$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$8 \to 9 \to 4 \to 2 = 2498$

$2498 (b a s e 10) = {(2498)}_{10}$

$2, 498_{10} = 2, 498_{10}$ .

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