Ufumbuzi - Tiger algebra Suluhishaji

2, 483

2,483

Maelezo kwa hatua

${(9 B 3)}_{16} = b a s e 10$

$9 B 3$ , $16$ , $10$ .

${(9 B 3)}_{16} = 9 \cdot 16^{2} + 11 \cdot 16^{1} + 3 \cdot 16^{0}$

$9 \cdot 16^{2} + 11 \cdot 16^{1} + 3 \cdot 16^{0} = 2483$

Hatua: $9 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $3 \cdot 16^{0}$ = $2, 483$ .

$\frac{2483}{10} = 248 r e m a \in d e r 3$

$\frac{248}{10} = 24 r e m a \in d e r 8$

$\frac{24}{10} = 2 r e m a \in d e r 4$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$3 \to 8 \to 4 \to 2 = 2483$

$2483 (b a s e 10) = {(2483)}_{10}$

$2, 483_{10} = 2, 483_{10}$ .

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