Ufumbuzi - Tiger algebra Suluhishaji

2, 473

2,473

Maelezo kwa hatua

${(9 A 9)}_{16} = b a s e 10$

$9 A 9$ , $16$ , $10$ .

${(9 A 9)}_{16} = 9 \cdot 16^{2} + 10 \cdot 16^{1} + 9 \cdot 16^{0}$

$9 \cdot 16^{2} + 10 \cdot 16^{1} + 9 \cdot 16^{0} = 2473$

Hatua: $9 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $9 \cdot 16^{0}$ = $2, 473$ .

$\frac{2473}{10} = 247 r e m a \in d e r 3$

$\frac{247}{10} = 24 r e m a \in d e r 7$

$\frac{24}{10} = 2 r e m a \in d e r 4$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$3 \to 7 \to 4 \to 2 = 2473$

$2473 (b a s e 10) = {(2473)}_{10}$

$2, 473_{10} = 2, 473_{10}$ .

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