Ufumbuzi - Tiger algebra Suluhishaji

2, 470

2,470

Maelezo kwa hatua

${(9 A 6)}_{16} = b a s e 10$

$9 A 6$ , $16$ , $10$ .

${(9 A 6)}_{16} = 9 \cdot 16^{2} + 10 \cdot 16^{1} + 6 \cdot 16^{0}$

$9 \cdot 16^{2} + 10 \cdot 16^{1} + 6 \cdot 16^{0} = 2470$

Hatua: $9 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $6 \cdot 16^{0}$ = $2, 470$ .

$\frac{2470}{10} = 247 r e m a \in d e r 0$

$\frac{247}{10} = 24 r e m a \in d e r 7$

$\frac{24}{10} = 2 r e m a \in d e r 4$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$0 \to 7 \to 4 \to 2 = 2470$

$2470 (b a s e 10) = {(2470)}_{10}$

$2, 470_{10} = 2, 470_{10}$ .

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