Ufumbuzi - Tiger algebra Suluhishaji

2, 281

2,281

Maelezo kwa hatua

${(8 E 9)}_{16} = b a s e 10$

$8 E 9$ , $16$ , $10$ .

${(8 E 9)}_{16} = 8 \cdot 16^{2} + 14 \cdot 16^{1} + 9 \cdot 16^{0}$

$8 \cdot 16^{2} + 14 \cdot 16^{1} + 9 \cdot 16^{0} = 2281$

Hatua: $8 \cdot 16^{2}$
+ $14 \cdot 16^{1}$
+ $9 \cdot 16^{0}$ = $2, 281$ .

$\frac{2281}{10} = 228 r e m a \in d e r 1$

$\frac{228}{10} = 22 r e m a \in d e r 8$

$\frac{22}{10} = 2 r e m a \in d e r 2$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$1 \to 8 \to 2 \to 2 = 2281$

$2281 (b a s e 10) = {(2281)}_{10}$

$2, 281_{10} = 2, 281_{10}$ .

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