Ufumbuzi - Tiger algebra Suluhishaji

2, 261

2,261

Maelezo kwa hatua

${(8 D 5)}_{16} = b a s e 10$

$8 D 5$ , $16$ , $10$ .

${(8 D 5)}_{16} = 8 \cdot 16^{2} + 13 \cdot 16^{1} + 5 \cdot 16^{0}$

$8 \cdot 16^{2} + 13 \cdot 16^{1} + 5 \cdot 16^{0} = 2261$

Hatua: $8 \cdot 16^{2}$
+ $13 \cdot 16^{1}$
+ $5 \cdot 16^{0}$ = $2, 261$ .

$\frac{2261}{10} = 226 r e m a \in d e r 1$

$\frac{226}{10} = 22 r e m a \in d e r 6$

$\frac{22}{10} = 2 r e m a \in d e r 2$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$1 \to 6 \to 2 \to 2 = 2261$

$2261 (b a s e 10) = {(2261)}_{10}$

$2, 261_{10} = 2, 261_{10}$ .

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