Ufumbuzi - Tiger algebra Suluhishaji

2, 224

2,224

Maelezo kwa hatua

${(8 B 0)}_{16} = b a s e 10$

$8 B 0$ , $16$ , $10$ .

${(8 B 0)}_{16} = 8 \cdot 16^{2} + 11 \cdot 16^{1} + 0 \cdot 16^{0}$

$8 \cdot 16^{2} + 11 \cdot 16^{1} + 0 \cdot 16^{0} = 2224$

Hatua: $8 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $0 \cdot 16^{0}$ = $2, 224$ .

$\frac{2224}{10} = 222 r e m a \in d e r 4$

$\frac{222}{10} = 22 r e m a \in d e r 2$

$\frac{22}{10} = 2 r e m a \in d e r 2$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$4 \to 2 \to 2 \to 2 = 2224$

$2224 (b a s e 10) = {(2224)}_{10}$

$2, 224_{10} = 2, 224_{10}$ .

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