Ufumbuzi - Tiger algebra Suluhishaji

2, 208

2,208

Maelezo kwa hatua

${(8 A 0)}_{16} = b a s e 10$

$8 A 0$ , $16$ , $10$ .

${(8 A 0)}_{16} = 8 \cdot 16^{2} + 10 \cdot 16^{1} + 0 \cdot 16^{0}$

$8 \cdot 16^{2} + 10 \cdot 16^{1} + 0 \cdot 16^{0} = 2208$

Hatua: $8 \cdot 16^{2}$
+ $10 \cdot 16^{1}$
+ $0 \cdot 16^{0}$ = $2, 208$ .

$\frac{2208}{10} = 220 r e m a \in d e r 8$

$\frac{220}{10} = 22 r e m a \in d e r 0$

$\frac{22}{10} = 2 r e m a \in d e r 2$

$\frac{2}{10} = 0 r e m a \in d e r 2$

$8 \to 0 \to 2 \to 2 = 2208$

$2208 (b a s e 10) = {(2208)}_{10}$

$2, 208_{10} = 2, 208_{10}$ .

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