Ufumbuzi - Tiger algebra Suluhishaji

1, 744

1,744

Maelezo kwa hatua

${(6 D 0)}_{16} = b a s e 10$

$6 D 0$ , $16$ , $10$ .

${(6 D 0)}_{16} = 6 \cdot 16^{2} + 13 \cdot 16^{1} + 0 \cdot 16^{0}$

$6 \cdot 16^{2} + 13 \cdot 16^{1} + 0 \cdot 16^{0} = 1744$

Hatua: $6 \cdot 16^{2}$
+ $13 \cdot 16^{1}$
+ $0 \cdot 16^{0}$ = $1, 744$ .

$\frac{1744}{10} = 174 r e m a \in d e r 4$

$\frac{174}{10} = 17 r e m a \in d e r 4$

$\frac{17}{10} = 1 r e m a \in d e r 7$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$4 \to 4 \to 7 \to 1 = 1744$

$1744 (b a s e 10) = {(1744)}_{10}$

$1, 744_{10} = 1, 744_{10}$ .

Je, maelezo haya yalikuwa na manufaa?

Tulifanyaje?

Jifunze zaidi na Tiger

Ubadilishaji wa msingi ni wa msingi kwa sayansi ya kompyuta, mifumo ya kidijitali, na nadharia ya namba.