Ufumbuzi - Tiger algebra Suluhishaji

1, 720

1,720

Maelezo kwa hatua

${(6 B 8)}_{16} = b a s e 10$

$6 B 8$ , $16$ , $10$ .

${(6 B 8)}_{16} = 6 \cdot 16^{2} + 11 \cdot 16^{1} + 8 \cdot 16^{0}$

$6 \cdot 16^{2} + 11 \cdot 16^{1} + 8 \cdot 16^{0} = 1720$

Hatua: $6 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $8 \cdot 16^{0}$ = $1, 720$ .

$\frac{1720}{10} = 172 r e m a \in d e r 0$

$\frac{172}{10} = 17 r e m a \in d e r 2$

$\frac{17}{10} = 1 r e m a \in d e r 7$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$0 \to 2 \to 7 \to 1 = 1720$

$1720 (b a s e 10) = {(1720)}_{10}$

$1, 720_{10} = 1, 720_{10}$ .

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