Ufumbuzi - Tiger algebra Suluhishaji

1, 712

1,712

Maelezo kwa hatua

${(6 B 0)}_{16} = b a s e 10$

$6 B 0$ , $16$ , $10$ .

${(6 B 0)}_{16} = 6 \cdot 16^{2} + 11 \cdot 16^{1} + 0 \cdot 16^{0}$

$6 \cdot 16^{2} + 11 \cdot 16^{1} + 0 \cdot 16^{0} = 1712$

Hatua: $6 \cdot 16^{2}$
+ $11 \cdot 16^{1}$
+ $0 \cdot 16^{0}$ = $1, 712$ .

$\frac{1712}{10} = 171 r e m a \in d e r 2$

$\frac{171}{10} = 17 r e m a \in d e r 1$

$\frac{17}{10} = 1 r e m a \in d e r 7$

$\frac{1}{10} = 0 r e m a \in d e r 1$

$2 \to 1 \to 7 \to 1 = 1712$

$1712 (b a s e 10) = {(1712)}_{10}$

$1, 712_{10} = 1, 712_{10}$ .

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